4x^2-6x=13

Solution for 4x^2-6x=13 equation:

4x^2-6x=13

We move all terms to the left:

4x^2-6x-(13)=0

a = 4; b = -6; c = -13;
Δ = b2-4ac
Δ = -62-4·4·(-13)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{61}}{2*4}=\frac{6-2\sqrt{61}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{61}}{2*4}=\frac{6+2\sqrt{61}}{8}
$